Explanation: Solve: \(dS_1 = mS \ln \left(\frac{T_2}{T_1}\right)\) \(= 10 \times 4200 \times \ln \left(\frac{373}{333}\right) = 4764.31 \, \text{JK}^{-1}\) \(dS_2 = \frac{dQ}{T} = \frac{mL_u}{T} = \frac{10 \times 2.26 \times 10^6}{373} = 60589.81\) মোট এনট্রপির পরিবর্তন, \(dS = dS_1 + dS_2\) \(= 4764.31 + 60589.81 = 65354.12 = 6.54 \times 10^4\) Ans. (E)