Explanation: Solve: \Delta m = (1 + 1.5 + 2.5) - 4.98 \\ = 0.02 \, \text{a.m.u} \\ \therefore \text{বন্ধন শক্তি} = \Delta mc^2 \\ = 0.02 \times 1.675 \times 10^{-27} \times (3 \times 10^8)^2 = 3 \times 10^{-12} \, \text{J} \\ = \frac{3 \times 10^{-12}}{1.6 \times 10^{-19} \times 10^6} \, \text{MeV} \\ = 18.75 \, \text{MeV} \\ \approx 18.62 \, \text{MeV} \quad [1 \, \text{a.m.u.} = 1.675 \times 10^{-27} \, \text{kg}] \\ \text{Ans. (B)}