Explanation: \(\text{Hints: কেন্দ্রাতিগ বল, } F = m\omega^2r\) \(\text{Solve: } F = \frac{mv^2}{r} = \frac{m\omega^2r^2}{r} \, [v = \omega r]\) \(\implies F = m\omega^2r \, [m = \text{ভর, } v = \text{রৈখিক বেগ, } \omega = \text{কৌণিক বেগ, } r = \text{ব্যাসার্ধ}]\) \(\implies F = 0.02 \times (3\pi)^2 \times 0.5 = 9\pi^2 \times 0.02 \times 0.5 = 0.09\pi^2\) \(\text{Ans. (C)}\)