Explanation: \(\text{Hints: } y = \frac{1}{2}gt^2, \, x = vt \\ \text{Solve: } y = \frac{1}{2}gt^2 \, [v_{y0} = 0, \, v_{x0} = 5 \, \text{ms}^{-1}] \\ \implies t = \sqrt{\frac{2 \times 0.6}{9.8}} = 0.3499 \, \text{s} \\ \text{আবার, } x = v_{x0} \times t \, [g_x = 0] \\ = 5 \times 0.3499 = 1.75 \\ \text{Ans. (C)}\)