\((4^{41}+4^{42}+4^{43})\) is divisible by -
A. 7
B. 13
C. 15
D. 17
E. none of these
Explanation: \(4^{41}+4^{42}+4^{43} = 4^{41}(1+4+4^2) = 4^{41}(1+4+16) = 4^{41}(21) = 4^{41}\times3\times7\). \(\therefore\) The expression is divisible by 7.
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