Solve: \(\text{CaCO}_3 + \text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2\text{O} + \text{CO}_2\) \(100 \, \text{g} \, \text{বা} \, 0.1 \, \text{kg} \, \text{CaCO}_3 \equiv 22.414 \, \text{L} \, \text{CO}_2\) \(\therefore \, 5 \, \text{kg} \, \text{CaCO}_3 \equiv \frac{22.414 \times 5}{0.1} \, \text{L} \, \text{CO}_2 \equiv 1120.7 \, \text{L} \, \text{CO}_2\)